John would make the 3-letter codes with diffenrent 5 vowels and 20 consonants with the condition that the middle letter must be vowel and the first letter and the third letter must be different from each other and are both consonant. How many different codes can be made?
","rationale_html":"There should be a vowel in the middle of the 3-letter code, which means that 5 letters can be in the middle. Then, 20 letters can be placed in the first letter and 19 letters can be placed in the last letter as they should be different letters. Thus, 20*5*19=1,900.
Therefore, the answer is E.
","correct_answer":["E"],"equiv_key":"a2b96e7c990e7c43f20a71eb","has_media":false,"has_mathml":false,"has_table":false,"section_label":"Mathematics","options":[{"label":"A","content_html":"1,980
","ord":0},{"label":"B","content_html":"2,020
","ord":1},{"label":"C","content_html":"2,100
","ord":2},{"label":"D","content_html":"2,200
","ord":3},{"label":"E","content_html":"1,900
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