Jim filled his dog's bowl with dog food. Starting at 8:00 am, Jim's dog ate exactly once an hour, consuming exactly 1/3 of the dog food remaining in the bowl at each feeding session. Approximately, what percent of the original food was in the dog's bowl right before the dog began to eat at noon of the same day?
","rationale_html":"The amount remaining after each feeding session is 2/3 of what was in the bowl.
There were four feeding sessions.
The amount remaining just before noon was (2/3)^4 = 16/81, which is about 20%.
The answer is A.
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