In how many arrangements can you arrange 3 green cones and 3 blue cones in a line along the boundary of football ground if no two cones of the same color are to be adjacent?
Correct answer: D
Explanation
BGBGBG or GBGBGB --> 2 ways,
Both 3 B's and 3 G's can be arranged in 3! ways.
Thus total 2*3!*3!=72.
D.
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Source: Algebra word problems from the AQuA-RAT dataset (Ling et al., 2017), published by Google DeepMind under the Apache License 2.0.
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AQuA-RAT items are crowdsourced algebra problems, not ACT questions. They carry five answer choices in the pre-2025 ACT Mathematics style and no ACT reporting category. Useful for drilling Preparing for Higher Math content; not a substitute for a real form.