A bag contains 11 candy bars: three cost 50 cents each, four cost $1 each and four cost $2
each. How many ways can 3 candy bars be selected from the 11 candy bars so that the total cost is more than $4?
Correct answer: C
Explanation
The ways of choosing 3 candy bars with a total cost over $4 include: choose 3 out of 4 (2 dollars each); choose 2 out of 4 (2 dollars each) and 1 from the other 7. So, the total number of ways is C4
3 + (7 C4
2 ) = 46. Incidentally, the total number ways of choosing 3 candy bars out of 11 is C11
3 = 165. So the probability of them costing more than $4 if they are randomly chosen is
C4
3 + (7 C4
2 )
C11
3
=
46/165
correct answer C
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AQuA-RAT items are crowdsourced algebra problems, not ACT questions. They carry five answer choices in the pre-2025 ACT Mathematics style and no ACT reporting category. Useful for drilling Preparing for Higher Math content; not a substitute for a real form.