Two trains are running with speed 30 km/hr. and 58km/hr. in the same direction. A man in the slower train passes the faster train in 18 seconds. The length (in metres) of the faster trains is:
Correct answer: D
Explanation
The relative speed = 58 - 30 = 28 Km/hr. = 140/18 m/s.
Therefore in 18 secs the faster train travels = (140/18) * 18 = 140
Answer D
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Source: Algebra word problems from the AQuA-RAT dataset (Ling et al., 2017), published by Google DeepMind under the Apache License 2.0.
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AQuA-RAT items are crowdsourced algebra problems, not ACT questions. They carry five answer choices in the pre-2025 ACT Mathematics style and no ACT reporting category. Useful for drilling Preparing for Higher Math content; not a substitute for a real form.