A picks a number from the bag where the bag consists of numbers from 1,2....23 and puts it in the same bag. Now, another person B picks a number from the bag. Find the probability that A has picked a greater number than B?
Correct answer: C
Explanation
If Ram draws 1, then Sam can draw anything from 2 to 23 = 22 ways
If Ram draws 2, then Sam can draw anything from 3 to 23 = 21 ways
. . . .
. . . .
If Ram draws 23, Sam's number of option = 0 ways.
Total required ways = 22 + 21 + 20 + . . . . + 0 = 22×232 = 253
Total ways of drawing two cards = 23×23
Required probability = 253/529=11/23
C
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AQuA-RAT items are crowdsourced algebra problems, not ACT questions. They carry five answer choices in the pre-2025 ACT Mathematics style and no ACT reporting category. Useful for drilling Preparing for Higher Math content; not a substitute for a real form.