Consider a school which consists of boys, girls and one teacher. There twice as many girls as boys. During prayer, this school follows a procedure where people bows to each other. Each girl and boy is required to bow to other girls, boys and their teacher. Each day 900 bows are completed. Find how many boys there are in the school ?
Correct answer: A
Explanation
Let number of boys = n
number of girls = 2n
Total number of bows by each girl and each boy to each other =(2n+n)C2 =(3n)C2
Total number of bows given to the teacher by girls = 2n
total number of bows given to the teacher by boys = n
total number bows =(3n)c2 + 2n + n
900 =3n*(3n-1)+2n+n
900 =9(n^2)-3n+3n
900 = 9(n^2)
n=10
A
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