3 men and 3 women need to be seated in 2 rows with 3 chairs in each row. All men have to be seated in the back row. How many ways can this be done?
A
6
B
12
C
24
D
36
E
72
Correct answer: D
Explanation
For one particular arrangement of men, say m1, m2, m3 women in the front row can be arranged in 3!=6 ways, as total # of arrangements of men is 3!=6 then total # of arrangements of men and women is 3!*3!=36.
Source: Algebra word problems from the AQuA-RAT dataset (Ling et al., 2017), published by Google DeepMind under the Apache License 2.0.
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AQuA-RAT items are crowdsourced algebra problems, not ACT questions. They carry five answer choices in the pre-2025 ACT Mathematics style and no ACT reporting category. Useful for drilling Preparing for Higher Math content; not a substitute for a real form.
id aqua_rat:b0f7b5788a9724cbe0328a7f78451763
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